NEET Chemistry Daily MCQs Practice Questions | 6 August, 2024

Due to increased repulsion among the electrons.

Due to decrease in effective nuclear charge.

Due to increased in effective nuclear charge.

Both (1) and (2)

 A – (q), B – (r), C – (p), D – (s)

A – (r), B – (p), C – (q), D – (s)

A – (r), B – (q), C – (s), D – (p)

A – (q), B – (s), C – (p), D – (r)

Rate of crystallization = Rate of unsaturation

Rate of dissolution = Rate of unsaturation

Rate of dissolution = Rate of saturation

Rate of crystallization = Rate of saturation

reciprocal proportion

conservation of mass

multiple proportion

constant composition

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.

If the Assertion is correct but Reason is incorrect.

If the Assertion is incorrect and Reason is correct.

Both statement I and II are correct.

 Both statement I and II are incorrect.

Statement I is correct but statement II is incorrect.

 Statement II is correct but statement I is incorrect.

CO₂

SiO₂

SnO₂

CaO

Diamminedichloridoplatinum (II)

Diamminedichloridoplatinum (IV)

Diamminedichloridoplatinum (0)

Dichloridodiammineplatinum (IV)

$\mathrm{K}\times {\mathrm{K}}^{\text{'}}=1$

$\mathrm{K}={\mathrm{K}}^{\text{'}}$

${\mathrm{K}}^{\text{'}}=\sqrt{\mathrm{K}}$

$\mathrm{K}=\sqrt{{\mathrm{K}}^{\text{'}}}$

to decrease [OH^–] conc.

to increase [OH^–] conc.

for making HCl

to decrease [Cl^–] conc.

 n = 5, l = 3, m = 0, s = +1/2

n = 3, l = 2, m = -3, s = -1/2

n = 3, l = 2, m = -2, s = -1/2

 n = 4, l = 0, m = 0, s = -1/2

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.

 If the Assertion is correct but Reason is incorrect.

 If the Assertion is incorrect and Reason is correct.

0.1 N Na₂SO₄

0.1 N MgsO₄

0.1 M Al₂(SO₄)₃

 0.1 M BaSO₄

TΔS > ΔΗ, ΔΗ = +ve, ΔS = +ve

TΔS > ΔΗ, ΔΗ = +ve, ΔS = -ve

TΔS = ΔΗ, ΔΗ = −ve, ΔS = -ve

TΔS = ΔΗ, ΔΗ = +ve, ΔS = +ve

n-Hexane

2,3-Dimethylpentane

2-Methylpentane

neo-Pentane